In the figure the straight lines I,m and n are parallel to each other and D is the mid-point of CE. С G B D F
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Julius Caesar
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Lines XY and MN intersect at O. If ∠POY = 90° and a : b = 2 : 3, find c.
Line OP is perpendicular to line XY. Hence ∠POY = ∠POX = 90°
∠POX = ∠POM + ∠MOX
90° = a + b ….(1)
Since a and b are in the ratio 2 : 3 that is,
a = 2x and b = 3x ….(2)
Substituting (2) in (1),
a + b = 90°
2x + 3x = 90°
5x = 90°
x = 90°/5 = 18°
a = 2x = 2 × 18°
a = 36°
b = 3x = 3 × 18°
b = 54°
Also , ∠MOY= ∠MOP + ∠POY
= a + 90°
= 36° + 90° = 126°
Lines MN and XY intersect at point O and the vertically opposite angles formed are equal.
∠XON = ∠MOY
c = 126°
Hope it helps
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