Question

in the figure, the two circles are drawn with same radius. prove that the two triangles ABC and ABD are equal. also prove the triangles are equilateral.​

Answer 1

Answer:

In △ABC, we have

AB=AC⇒∠ABC=∠ACB

(angles opposite to equal sides.)

Again in △DBC, we have

DB=DC ......... (given)

⇒∠DBC=∠DCB (angles opposite to equal sides).

Hence we obtain

∠ABC−∠DBC=∠ACB−∠DCB.

This gives

∠ABD=∠ACD. [henceproved]