Question

In the figure there are three infinite long thin sheets having surface

charge density +2σ, -2σ and +σ respectively. Give the magnitude and

direction of electric field at a point to the left of sheet of charge density +2σ and to the right of

sheet of charge density +σ.​

Answer 1

Answer:

The charge of magnitude +q present inside the spherical shell induces a charge of magnitude −q 0n the inner part of the shell. Therefore, for the charge on the inner part, the surface charge density will be due to −q.

It is given by:

σ

1

=

surface area of inner part

Totalcharge

⇒

4πr

1

2

−q

The charge on the outer shell will be +q and the surface charge density at the outer part will be due to sum of q and Q charges present on the outer shell.

σ

2

=

Outersurfacearea

Totalcharge

=

4πr

2

2

Q+q

...

Explanation:

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