Question

in the figure thes line AP And BR are parallel.then distance between them are 3cm. And BC=EF=QR = 4cm

Find the area of the triangle ABC?

Find the area of the triangle DEF?

Find the area of the triangle PQR? ​

Answer 1

Answer:

6 cm^2 , 8 cm^2

Step-by-step explanation:

Area of ABC = 1/2 × 4 × 3 = 6 cm^2

In triangle DEF , EF = 4 cm and height = 4 cm

Area of DEF = 1/2 × 4 × 4 = 8 cm^2

sorry can't solve 3rd one

Answer 2

Answer:

Area of tringles with same height and same base

the AP and BR are Parallel so height of AB = DO=PS

O is the mid point of EF

S is the striaight vertical line from P

Step-by-step explanation:

for all triangle b=4cm and h=3cm

Area of ∆ABC=1/2×b×h=1/2×4×3=6cm²

Area of ∆DEF=1/2×b×h=1/2×4×3=6cm²

Area of ∆PQR=1/2×b×h=1/2×4×3=6cm²

so finally conclude that if base and height are equal than area is also equal

Area of {∆ABC=∆DEF=∆PQR}=6cm²