Question

In the figure three angles are formed on a straight
line. Find the angles.​

Answer 1

Answer:

<AOC+<COD+<DOB=180(ANGLES ON A STRAIGHT LINE)

2x+2x+2x=180

6x=180

x=180/6

x=30

so,<AOC=<COD=<DOB=2x=2*30=60

Step-by-step explanation:

<AOC=60°

<COD=60°

<DOB=60°

Answer 2

Hi mate...:*☆

Hope u are safe during this pandemic !!!

Here is ur answer :-

As these angles are adjacent and on a straight line, they are forming linear angle.

This means, their sum would be supplementary i.e, 180°

So, we got an equation to compute -

∠AOC + ∠COD + ∠DOB = 180°

$2x+2x+2x= 180\\\\6x=180\\\\x=\frac{180}{6} \\\\x=30^{o}$

⇒ x = 30°

Now, as x = 30°, values of each angles is -

• ∠AOC = 2x = 2*30° = 60°

∠AOC = 60°

• ∠COD = 2x = 2*30° = 60°

∠COD = 60°

• ∠DOB = 2x = 2*30° = 60°

∠DOB = 60°

Therefore, each angle formed here, is of 60°

Some more to know :

☞ Two adjacent angles are said to be linear angles if their non-common arms are two opposite rays.

☞ As, these rays are opposite they would form a straight line.

☞ Now, as these angles form straight line, their sum would be always supplementary i.e 180°