In the figure, three lines AB, CD and EF intersect at O. Find the
value of ‘x’ and also find angles AOE and BOD.
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It is given that ∠BOD = 180°
from the figure we know that ∠BOD and ∠AOC are vertically opposite angles
∠AOC = ∠BOD = 40°
It is given that ∠AOE = 35°
from the figure we know that ∠BOF and ∠AOE are vertically opposite angles
∠AOE = ∠BOF = 35°
from the figure, we know that AOB is a straight line
so it can be written as
∠AOB = 180°
we can write it as
∠AOE + ∠EOD + ∠BOD = 180°
by substituting the values
35° + ∠EOD + 40°
=180°
∠EOD = 105°
from the figure, we know that ∠COF and ∠EOD are vertically opposite angles
∠COF = ∠EOD = 105°
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