In the figure, triangle ABC and triangle DBC are on the same base BC. If AB=AC and BD=CD, then prove that angle ABD=angle ACD.
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given ,
BA=AC (GIVEN)
BD=CD (GIVEN)
AD=AD (COMMON)
triangle DBA=~triangle DCA (SSS)
by usimg criteria SSS
Hence, both triangle are congrent
so, the angle ABD=angle ACD
verified.
BA=AC (GIVEN)
BD=CD (GIVEN)
AD=AD (COMMON)
triangle DBA=~triangle DCA (SSS)
by usimg criteria SSS
Hence, both triangle are congrent
so, the angle ABD=angle ACD
verified.
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