in the figure, triangle abc is a right angled triangle at c and d is the midpoint bc. prove that ab²=4ad²-3ac²
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ab^2= ac^2+bc^2 -----1
ad^2=ac^2+1/4bc^2------2
putting the values
ac^2+bc^2=4×ac^2+1/4bc^2-3ac^2
ac^2+bc^2=4ac^2+bc^2-3ac^2
ac^2+bc^2=ac^2+bc^2
hence proved
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ad^2=ac^2+1/4bc^2------2
putting the values
ac^2+bc^2=4×ac^2+1/4bc^2-3ac^2
ac^2+bc^2=4ac^2+bc^2-3ac^2
ac^2+bc^2=ac^2+bc^2
hence proved
PLEASE MARK IT AS BRAINLYST
deepanjalipande67:
1/4 bc^ ?????? How ?
This is wrong
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