in the figure triangle ABC is a right Triangle at A. Q and R are point on BC producer and BC respectively. there is a point P such that QP parallel AB and RP parallel AC. find angle P
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Given : < A = 90°
To Find : < P
Solution : Since AC || PS where AB is transversal.
< BAC = < BSR [Corresponding angles]
< BSR = 90°
Since PQ || AB where PS is transversal.
< BSR = < RPQ [Alternate angles]
< RPQ = 90
{ Answer : 90° } Answer : 90°
Have great future ahead!
Given : < A = 90°
To Find : < P
Solution : Since AC || PS where AB is transversal.
< BAC = < BSR [Corresponding angles]
< BSR = 90°
Since PQ || AB where PS is transversal.
< BSR = < RPQ [Alternate angles]
< RPQ = 90
{ Answer : 90° } Answer : 90°
Have great future ahead!
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