Question

In the figure triangle ABC is an isosceles triangle. If AB=AC ,Write the measures of the other two angles​

Answer 1

Answer:The measure of other two angles is 65°
Step-by-step explanation
∠ABC=∠ACB(The opposite angles of equal sides are equal)
Let the other two angles as x
Sum of all the angles of a triangle=180°
ATQ
50°+x+x=180°
50°+2x =180°
2x =180°-50°
2x =130°
x =130/2
x =65°

Answer 2

Answer:

• 65° is the measures of other two angles.

Step-by-step explanation:

According to the Question

It is given that,

ABC is an isosceles triangle in which AB = BC and also ∠A = 50 °

We have to calculate the measures of two other angles .

As Per given Condition

➺ AB = BC

then

➺ ∠C = ∠B

Angles opposite to equal sides are equal .

Now we know that Sum of all angles in a triangle is 180° .

Let angle ∠C & ∠B be x .

Now putting the value we get

➺ ∠A + ∠B + ∠C = 180°

➺ ∠C + ∠B + 50° = 180°

➺ ∠C + ∠B = 180° - 50°

➺ ∠C + ∠B = 130°

➺ x + x = 130°

➺ 2x = 130°

➺ x = 130/2

➺ x = 65°

Since both angles are equal

Therefore measures of other two angles will be 65°