in the figure triangle ABC is circumscribing a circle. find the length of Bc
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Answered by
324
Hi .
here is your answer
AR=AQ=4cm (tangent to circle)
BR=BP=3cm(tangent to a circle)
AC=AQ+QC
11=4+QC
QC=11-4=7
QC=CP =7cm(tangent to a circle)
BC=BP+PC
BC=3+7
BC=10cm
hope you don't have any problem left
here is your answer
AR=AQ=4cm (tangent to circle)
BR=BP=3cm(tangent to a circle)
AC=AQ+QC
11=4+QC
QC=11-4=7
QC=CP =7cm(tangent to a circle)
BC=BP+PC
BC=3+7
BC=10cm
hope you don't have any problem left
Answered by
21
Given : triangle ABC is circumscribing a circle
To Find : Length of BC
Solution:
AR = AQ Equal tangents
AR = 4 cm
=> AQ = 4 cm
AC = AQ + QC
AC = 11 cm , AQ = 4 cm
=> 11 = 4 + QC
=> QC = 7 cm
QC = PC Equal tangents
=> PC = 7 cm
BP = BR Equal tangents
BR = 3 cm
=> BP = 3 cm
BC = BP + PC
=> BC = 3 + 7
=> BC = 10 cm
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