Question

In the figure triangle adb and triangle cdb are drawn on the same base bd. if ac and bd intersects at o,then prove that a (triangle adb)/a(triangle cdb) = ao/co​

Answer 1

Area of ΔADB/Area of ΔCDB     =     AO/CO

Step-by-step explanation:

Draw AE ⊥ to BD from A and draw CF ⊥ to BD from C.

In ΔAEO and ΔCFO

∠AOE = ∠COF (Vertically opposite angles)

∠AEO = ∠CFO = 90°

Hence, ΔAEO is similar to ΔCFO by AA similarity theorem.

When two triangles are similar, then the ratio of the areas of two triangles is equal to the ratio of square of their corresponding sides.

Area of ΔAEO/Area of ΔCFO    =    AO²/CO²      =     AE²/CF²

AO/CO  =   AE/CF                             ..............................................(1)

Area of ΔADB/Area of ΔCDB     = (1/2 * BD * AE) / (1/2 * BD * CF)

                                                    =  AE/CF

                                                    = AO/CO (from (1) )

Hence proved.

To learn more;

https://brainly.in/question/5825734

https://brainly.in/question/15537708

Answer 2

Answer:

i hope it helps you !!!!!!!!