Math, asked by shijipavithran, 16 hours ago

In the figure two circles intersect at D. Angle BCD = 80 degree, Angle EFG = 70 degree. what is the measure of angle BAD? what is the measure of angle EDG?​

Answers

Answered by ITZURADITYAKING
18

Answer:

Given,

∠BAD=70

, ∠ABD=56

and ∠ADC=72

.

ABCD is a cyclic quadrilateral.

We know, the sum of opposite angles of a cyclic quadrilateral is 180

o

.

Therefore,

∠BAD+∠BCD=180

∠BCD=180

−∠BAD

∠BCD=180

−70

=110

Also, ∠ADC+∠ABC=180

o

72

+(56

+∠CBD)=180

∠CBD=180

−128

=52

.

In △BCD,

∠BCD+∠DBC+∠BDC=180

...[Angle sum property]

110

+52

+∠BDC=180

∠BDC=18

Answered by manasi3151
1

Answer:

BAD=70

, ∠ABD=56

and ∠ADC=72

.

ABCD is a cyclic quadrilateral.

We know, the sum of opposite angles of a cyclic quadrilateral is 180

o

.

Therefore,

∠BAD+∠BCD=180

∠BCD=180

−∠BAD

∠BCD=180

−70

=110

(i).

Also, ∠ADC+∠ABC=180

o

72

+(56

+∠CBD)=180

∠CBD=180

−128

=52

(ii).

In △BCD,

∠BCD+∠DBC+∠BDC=180

Angle sum property]

110

+52

+∠BDC=180

∠BDC=18

.(i).

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