Question

In the figure,
two circles of radii 7cm each touch each other
externally. ABCD is rectangle.
Find the area of shadded region.​

Answer 1

Answer:

Step-by-step explanation:

since r (radius )= 7cm

thus CD =2r 14cm

since abcd is arectangle thus theta = 90

are of shaded region =area of abcd-arof 2 quadrants

= lb- πr²/ 2

=14×7-22/7 ×7×7/2

= 98-77

=21 cm ²

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Answer 2

The required area  of shaded region is 21 cm²

Step-by-step explanation:

Given : Radius of circle = 7 cm

Now DC= 2 x radius of circle= 2 x 7 = 14 cm

AD= 7 cm (Radius of circle)

Therefore

Area of rectangle = length x breadth

                             = AD x DC = 14 x 7 = 98 cm²

Now as ABCD is a rectangle

∠ADC=∠DCB= 90° (Angles of rectangle)

Area of 2 quadrants = $2 \times \dfrac{\pi r^2 \theta}{360}$

where ∅ = 90°

Area = $2 \times\dfrac{22 \times 7 \times 7 \times 90^\circ}{7 \times 360 ^\circ} = 77 cm^2$

Area of shaded region = area of rectangle - area of 2 quadrants

                                      = 98-77=21 cm²

Hence the required area is 21 cm²

# Learn more

Find the area of the shaded region

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