in the figure two circles with centres P and Q intersect at R and S. prove that Angle PRQ =angle psq
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In a Given equation we can prove in the
P and Q are the center of the circle
Construction
Join PQ
To prove
Angle PQR=angle PSQ
Now,
In Δ PQR and Δ PSQ
PR=PS
OR=QS
PQ=QP
Therefor,
Δ PQR is congruent to Δ PSQ,
So , hence the proved
Angle PQR=angle PSQ
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