in the figure two Parallel Lines p and q are intersected by a transversal are such that angle 2 : angle 3 is equal to 8 :7 find all the angles
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<2+<3=180°
therefore...<2=180°×[8/(8+7)]=96°
and <3=180°-96°=84°
now ...<1=<3=84°{vertically opposite ang)
<4=<2=96°(vertically opposite ang)
<5=<3=84°(alternate anglesand p||q)
<6=<4=96°(alternate anglesand p||q)
<7=<5=84°(vertically opposite ang)
<8=<6=96°(vertically opposite ang)
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