in the figure two straight lines AB and CD intersect at O.if COT =60 degrees find a,b,c
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<AOC=<DOB(vertically opposite angle)
CD is a line
60°+b+4b=180°
60°+5b=180°
5b=180°-60°
5b=120°
b=24°
again CD is a line
60°+24°+a=180°
84°+a=180°
a=180°-84°
a= 96°
AB is a line
96°+2c=180°
2c=180°-96°
2c=84°
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