Question

in the figure two tangents TP and TQ are drawn to a circle with centre O from an external point that PTQ =2 OPQ​

Answer 1

Answer:

To prove :- <PTQ = 2<OPQ

Step-by-step explanation:

TP =TQ

Hence,

$< tpq = < pqt \\ in \: triangle \: tpq \\ < tpq = (180 - < ptq) \div 2$

<OPT= 90

<OPQ= 90-<TPQ

= 90-((180 - <PTQ)/2)

= < PTQ /2

=> <PTQ = 2< OPQ.