Question

in the figure we have angle abc is equal to angle ACB and angle 3 is equal to angle 4 show that angle 1 is equal to angle 2​

Answer 1

Answer:<1=<2

<3=<4

Adding <1 to both angles

<3+<1 = <4+<1

As mentioned above, <1=<2

Therefore, <3+<1=<2+<4

Which means: <ABC = <DBC

The Euclid's axiom used here is: "If equals are added to equals, the wholes are equal."

Figure is not given plz upload figure to make easier for us thanks if u understand then plzzz mark me as a brainlist

Answer 2

Given: ∠ABC=∠ACB --------------(1)

           ∠4=∠3 --------------(2)

To prove: ∠1=∠2

Proof: ∠1= ∠ABC-∠4

          ∠2= ∠ACB-∠3

Subtracting (2) from (1),

∠ABC-∠4= ∠ACB-3 (If equals are subtracted from equals, the remainders are equal)

Therefore,

                ∠1=∠2

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