Question

in the figure what is the value of x​

Answer 1

Answer:

x=95°

Step-by-step explanation:

In ΔPQR,

∠QRS=∠QPR+∠PQR(Exterior angle sum property)

∠QRS=35°+30°

∠QRS=65°

In ΔRTS,

∠QTS=QRS+∠TSR(Exterior angle sum property)

x=65°+30°

x=95°

Answer 2

Answer:

X=95°

Step-by-step explanation:

PRS=180°

angle P + angle Q+ angle R=180° (as it forms a triangle )

so, 35°+30°+ y = 180°

= y = 180°- 65° = 115°

thus , angle QRS = 180°- angle QRP

= 180°-115° = 65°

angle x = angle xSR + angle QRS ( THE SUM OF TWO ANGLES IS EQUAL TO THE VALUE OF OPPOSITE EXTERIOR ANGLE IN A TRIANGLE)

Thus, angle X= 30°+65°=95°

angle x=95°