Question

in the figure,/x=62°,/xyz=54° if yo and zo are the bissectare of /xyz and
/xzy respectively of ∆xyz,find /ozy and /yoz.​

Answer 1

Step-by-step explanation:

Angle X=62°

Angle XYZ=54° .................... you have given in question (text)

angle X + angle xyz + angle Z = 180°............ angle addition property of triangle

62 + 54 + angle Z = 180°

116 + angle z = 180°

angle Z = 180 - 116

angle Z = 64°

OZ is angle bisector of angle XZY

angle OZY = 32°................1

similarly OY is angle bisector of angle XYZ

angle OYZ= 27°................... 2

in triangle OYZ,

angle OYZ+ angle OZY+ angle YOZ=180°............. angle sum property of triangle

27 + 32 + angle YOZ= 180

59 + angle YOZ = 180

angle YOZ= 121°

ANS: angle OZY=32°

angle YOZ= 121°