Question

in the figure x, y are the midpoint of the side of the right angled triangle PQR. if xy=4cm, PR=10cm find the lengths of the side of triangle PQR and triangle PXY​

Answer 1

Answer:

Explanation:

OAB = ½ CAB …….(i) [AO is the bisector of CAB]

OBA = ½ CBA …….(ii) [BO is the bisector of CBA]

In ABC

CAB+CBA+C = 180˚ [Angle sum property of triangle]

CAB+CBA+70˚ = 180˚

CAB+CBA = 180˚-70˚

CAB+CBA = 110

Multiply both sides by ½

½ CAB+½ CBA = 55˚

OAB+OBA = 55˚ ….(iii) [From (i) and (ii)]

In AOB

AOB+OAB+OBA = 180˚ [Angle sum property of triangle]

AOB+55˚ = 180˚ [From (iii)]

AOB = 180˚-55˚ = 125˚

Hence measure of AOB is 125˚.