in the figure xp, xq and xr are the tangents to the circles. if the length of xq is 9 cm. find the length of the tangent XR
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From the figure, there is an external point X from where two tangents, XP and XQ, are drawn to the circle.
XP=XQ
(The lengths of the tangents drawn from an external point to the circle are equal.)
Similarly,
AP=AR
BQ=BR
XP=XA+AP --------- (1)
XQ=XB+BQ --------- (2)
By substituting AP=AR in equation (1) and BQ=BR in equation (2), we get
XP=XA+AR
XQ=XB+BR
Since the tangents XP and XQ are equal, we get
XA+AR=XB+BR.
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