Question

In the figure, XY ǁ MN then prove that △XTY ~ △MTN​

Answer 1

Step-by-step explanation:

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Answer 2

Solution :-

In ∆XTY and ∆NTM we have,

→ ∠XTY = ∠NTM { Vertically opposite angles }

→ ∠TXY = ∠TNM { since XY ǁ MN , alternate interior angles . }

→ ∠TYX = ∠TMN { since XY ǁ MN , alternate interior angles . }

then,

→ ∆XTY ~ ∆NTM { By AAA Similarity .}

Note :- ∆XTY is similar to ∆NTM not ∆MTN .

Learn more :-

In the figure along side, BP and CP are the angular bisectors of the exterior angles BCD and CBE of triangle ABC. Prove ∠BOC = 90° - (1/2)∠A .

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