In the figure Y is the midpoint of EF. If XY = YZ, angle EXY = angle FZY = 90° show that DE = DF.
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Answer: I hope it helps : )
Step-by-step explanation:
EXY ≅FZY ( by RHS )
∴<XEY = <ZFY (by CPCT )
∴DE = DF (by- converse of isosceles triangle theorem)
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