Question

In the figures AB AC are the two Tangent drawn from the point A to the circle with center of. If angle BOC = 130° then find angle BAC

Answer 1

Step-by-step explanation:

∠ABO=∠ACO=90

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In a quadrilateral, the sum of the angles is 360

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.

∠BAC+∠BOC+∠ABO+∠ACO=360

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∴∠BAC+∠BOC=180

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∠BOC=180

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−40

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∠BOC=140

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So, option C is the answer