Math, asked by rohit75dogras, 2 months ago

in the figures below find the marked angles:
A
40%
25
Х
95°
Z
edc
35°
30°
°
zdy 65
D
S
B
R
C​

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Answers

Answered by MPLKK
1

Answer:

See the explanation

Step-by-step explanation:

Figure 1.

In ∆ABD By the angle sum property,

40°+30°+y=180°

y=110°

Now, angles y and z form linear pair.

So,

y+z=180°

110+z=180°

z=70°

Now in ∆ADC, by angle sum property,

We have,

x+z+95°=180°

x+70°+95°=180°

x=15°

Figure 2

In ∆PQR,

By the angle sum property,we have

25°+35°+z=180°

z=120°

Also in the ∆TRS by the exterior angle property,

x+65°=z

120°=x+65°

x=55°

By linear pair,

y+z=180°

y+120°=180°

y=60°

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