in the figures below find the marked angles:
A
40%
25
Х
95°
Z
edc
35°
30°
°
zdy 65
D
S
B
R
C
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Answer:
See the explanation
Step-by-step explanation:
Figure 1.
In ∆ABD By the angle sum property,
40°+30°+y=180°
y=110°
Now, angles y and z form linear pair.
So,
y+z=180°
110+z=180°
z=70°
Now in ∆ADC, by angle sum property,
We have,
x+z+95°=180°
x+70°+95°=180°
x=15°
Figure 2
In ∆PQR,
By the angle sum property,we have
25°+35°+z=180°
z=120°
Also in the ∆TRS by the exterior angle property,
x+65°=z
120°=x+65°
x=55°
By linear pair,
y+z=180°
y+120°=180°
y=60°
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