in the figures if bc =3 bd =7 then find A (triangle abc )/A (triangle abd)
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Answer:
The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.
It is given that DE∣∣AB,AD=7 cm, CD=5 cm and BC=18 cm.
Using the basic proportionality theorem, we have
CA
CD
=
AB
DE
=
CB
CE
⇒
CA
CD
=
CB
CE
⇒
12
5
=
18
CE
⇒18×5=12CE
⇒12CE=90
⇒CE=
12
90
=7.5
Since CE=7.5 cm, therefore,
CB=CE+EB
⇒18=7.5+EB
⇒EB=18−7.5=10.5
Hence, BE=10.5 cm and CE=7.5 cm.
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2
Step-by-step explanation:
ANSWER:
Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.
Given:
BC = 9, AB = 5, PQ = 6 and QR = 10.
∴A(△ABC)A(△PQR)=AB×BCPQ×QR=5×96×10=34
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