In the figures two circles with centres A and B touch each other externally .PM=15cm is tangent to a circle with centre A and QN=13cm is tangent to a curcke with centre B frok external points P and Q respectively. If PA =17cm and BQ=12cm ,Find distance between A and B.
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The angle between a tangent and radius is right angle.angles BNQ and AMP are right angles
The triangle PAM is a right angled triangle, with PA being the hypotenuse.
Using Pythagoras theorem, the radius of the circle with centre A is found as
AM = Sqrt ( 172 - 152)
AM = 8 cm
Similarly, the radius of circle with centre B is found as
BM= sqrt( 132 -122)
BM = 5cm
Clearly , the distance between the centre is the sum of radii of the two circles ( AC +BC)
Required distance = 5cm + 8cm = 13 cm.
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