Question

in the
Find out the number of elections, protons and neutrons
following:
14 N
7​

Answer 1

Explanation:

Nitrogen-14 is actually an isotope of nitrogen, so right from the start, you can say that it is a neutral atom.

Isotopes are atoms that have the same number of protons but different numbers of neutrons in the nucleus. You know that nitrogen-14 has

7

protons in the nucleus because it is an isotope of nitrogen, which has an atomic number equal to

7

.

Because nitrogen-14 is a neutral atom, the number of protons it has in its nucleus must be equal to the number of electrons that surround its nucleus.

neutral atom

⇒

no. of protons = no. of electrons

Now, in order to find the number of neutrons present in the nucleus of a nitrogen-14 atom, you must use its mass number. The mass number of an isotope is added to the name of the isotope.

In this case, you have

nitrogen-

14

⇒

mass number

=

14

The mass number of an atom tells you the number of protons and neutrons located in the nucleus.

So you can say that

no. of protons + no. of neutrons

=

14

This implies that a nitrogen-14 atom contains

(

14

.

protons + neutrons

)

−

7 protons

=

7 neutrons

Now, a nitrogen atom, regardless of its mass number, will always form

3

−

anions,

N

3

−

. In other words, any nitrogen atom will take in

3

electrons to complete its octet--this happens because nitrogen is located in group

15

of the Periodic Table.

Answer 2

Answer:-

• The element is Nitrogen here.

The symbol given by

$\\ \sf\longmapsto 7^{N^{14}}$

Here

• Atomic mass=14
• Atomic number=7

We know

$\\ \sf\longmapsto No\:of\:protons=Atomic\:Number$

$\therefore\underline{\boxed{\bf No\:of\:Protons=7}}$

Again

$\\ \sf\longmapsto No\:of\:protons=No\:of\:electrons$

$\therefore\underline{\boxed{\bf No\:of\:electrons=7}}$

And

$\\ \sf\longmapsto No\:of\:Neutrons=Atomic\:Mass-No\:of\:Protons$

$\\ \sf\longmapsto 14-7=7$

$\therefore\underline{\boxed{\bf No\:of\:Neutrons=7}}$