Question

in the fiqure ABCD is a triangle. the area triangle AEB is 18cm2.what is the area of ADB. find the area of rectangle ABCD.
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Answer 1

In △BCE

⇒EB

2

+EC

2

=BC

2

⇒EB

2

=BC

2

−EC

2

⇒EB=

100−64

=

36

=6cm

Area of the △EBC=

2

1

×EB×EC

=

2

1

×6cm×8cm=24cm

2

Area of rectangle ABCD=18cm×10cm=180cm

2

Area(shaded region) =ar(rectangle)−ar(△BCE)

180cm

2

−24cm

2

=156cm

2