Question

in the first figure i2>i1 (i1= angle of incidence and i2=angle of emergence)but in the second both are i1 .in the first figure i1=i2 and in the second figure i1=i2 how they became same and equalised.plz help me.write the correct answer or else u will be reported .​

Answer 1

Answer:

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Let a right ray AO from a source A strike a plane mirror at O and reflected as ray OB. Let B be a point on ray OB and let ON be the normal to the mirror at O. The angle of incidence is ‘x’ and angle of reflection is ‘y’, as shown. Let ‘t’ be the time taken for the ray to travel the distance AO + OB and ‘c’ be the velocity of light, which is a constant.

The time ‘t’ can be worked out

t = C/AO + C/OB

t= c[1/√a2 + p2 + 1/ /√(l-a)2 + q2 ]

Therefore, the derivative dt/da must be 0

0 = [a/√a2 + p2 = (l-a) /√(l-a)2 + q2 ]

[1/√a2 + p2 =√(l-a)2 + q2 ]

But as per trigonometry, this is same as sin(x) = sin(y) or x = y.

Hence,

The Angle of Incidence = Angle of Reflection

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