Question

In the first second of its flight a rocket release 1/60th of its mass with a velocity of 2400m/s , the acceleration of the rocket is (a) 19.6ms-2 (b) 30.2ms-2 40ms-2 (d) 49.8ms-2

PLEASE EXPLAIN IN DETAIL
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Answer 1

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Given:

• Velocity = 2400m/s
• Time = 1 second
• Mass = M/40

Solution:

The ejection force of the Rocket is :-

$f = \frac{mv}{t}$

$f = m60 \times 2400 \times 1$

$f = 40m$

Acceleration = F/M

$a = \frac{40m}{m}$

Therefore, Acceleration of the rocket = 40m/s².