In the first term of an AP is 3, the sum of first 5 terms is 1/11th of the sum of next 5 terms .find the 20th term
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a=3 & S5=1/11 (S10-S5)
12S5=S10
30(2a+11d)=5 (2a+9d)
6 (2a+11d)= 2a+9d
10a=-57d
a=3
30=-57d
d=-10/17
a20=3-10/17
=(57-10)/17
=47/17
12S5=S10
30(2a+11d)=5 (2a+9d)
6 (2a+11d)= 2a+9d
10a=-57d
a=3
30=-57d
d=-10/17
a20=3-10/17
=(57-10)/17
=47/17
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