In the first term of gp is 1 the sum of third and fifth term is 90 find common ratio gp
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Let a, ar, ar^2, ar^3, ar^4.... are in GP.
Given a= 1, r is common ratio.
Then third term is r^2 and 5th term is r^4 & their sum is 90.
Hence, r^4 + r^2 = 90
r^4 + r^2 - 90 = 0
Solving this, we get
r^2= - 10 (or) +9
r^2 = 9
r = +3 or -3 (r is common ratio)
Third term is r^2 = +9 (even if r = 3 or -3)
Fifth term is r^4 = +81,
Hence, Gp is
1, 3, 9, 27, 81,... (When r= 3)
and 1, -3, 9, -27, 81,.... (When r= --3)
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