Question

In the following AB, find the missim 13 S. (iv) - 4 4. Which term of the AP:3.8. 13. 18. 5. Find the number of terms in each of the​

Answer 1

Answer:

For the following A.P : 3,8,13,18,------, 78  

First term (t1) = a = 3,common difference (d) = 8 - 3 = 5 and last term (tn) = 78  

The general term of A.P is  

tn = a + (n - 1) d  

78 = 3 + (n - 1)5  

78 = 3 + 5n - 5  

78 = - 2 + 5n  

78 + 2 = 5n  

80 = 5n  

80/5 = n  

16 = n  

n= 16  

16th term of A.P : 3,8,13,18,is 78.

Step-by-step explanation:

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Answer 2

Answer:

The given sequence is 3, 8, 13, 18, ....78.

'a' = 3, 'd' = 5, last term = 78, 'n' = ?

t

n

=a+(n−1)d

⟹78=3+(n−1)5

⟹78=3+5n−5

⟹78=5n−2

⟹5n=80orn=16.

The 16th term is 78.