Math, asked by yoganand32, 1 year ago

in the following ap find the missing term

Attachments:

Answers

Answered by srijonrick
2

The A.P. series is :5, __, __, 5+3d=9\frac{1}{2}

Now, from the data it is evident that the first term of the A.P. series is 5.

And the last term is  9\frac{1}{2} .

Now since it is an A.P. series there must exist a common difference, let it be d .

So, now we can figure the given series as below:-

5,5 + d,5 + 2d,5 +3d

Now from the above analysis it is evident that:-

5+3d=9\frac{1}{2}

Therefore, d=\frac<strong>{3}{2}</strong>

Therefore, the required terms are:-

2^{nd}  term = 5+d=5+ \frac{3}{2}=5 \frac{3}{2} =\frac<strong>{13}{2}</strong>

and

3^{rd}term=5+2d=5+2* \frac{3}{2}=5+3=<strong>8</strong>


srijonrick: Sorry, some odd formats are there in the answer i.e. d=3/2, 2nd term =13/2 and 3rd term= 8 please ignore those entities with angle brackets.
yoganand32: ooookey bros
Similar questions