Question

in the following APs , find the missing terms in the box: 5,_,_,9 1/2

Answer 1

a= 5

4th term

T4 = 5+3d

$\frac{19}{2} = 5 + 3d \\ \\ \frac{19}{2} - 5 = 3d \\ \\ \frac{19 - 10}{2} = 3d \\ \\ d = \frac{3}{2}$


Second term

$5 + \frac{3}{2} \\ \\ = \frac{13}{2}$
Third term

$5 + 2 \times \frac{3}{2} \\ \\ = 8$
So,
5, 6 1/2,8,9 1/2