In the following arrangement, all the odd numbers were placed in such a way that in the ith row, there are i consecutive odd numbers, 1 3 5 7 9 11 13 15 17 19 ...... . . . Then the first term (on the left) of 20 row is: (A)289 (B) 381 (C) 383 (D) 385
Answers
Answered by
3
Answer:
three consecutive odd numbers are 13, 15 and 17 whose sum is 45.
Step-by-step explanation:
Similar questions