In the following arrangement of four resistors find the total current drawn from the circuit.
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Answer:
0.3 A
Explanation:
In the figure,
R1 and R2 are in series,
Effective resistance Rs1=10+10=20 Ω
R3 and R4 are in series,
Effective resistance Rs2=10+10=20 Ω
Rp1 and Rp2 are in parallel with each other,
Effective resistance 1/Rp=1/20+1/20
Rp=10 Ω
From Ohm's Law,
V=IR
3=I×10
I=3/10
=0.3 A
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Explanation:
i hope this will help U .........total current will be 7.5 Ampre
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