Question

In the following arrangement of four resistors find the total current drawn from the circuit.
Please answer this question...

Answer 1

Answer:

0.3 A

Explanation:

In the figure,

            R1 and R2 are in series,

          Effective resistance Rs1=10+10=20 Ω

         R3 and R4 are in series,

          Effective resistance Rs2=10+10=20 Ω

    Rp1 and Rp2 are in parallel with each other,

           Effective resistance 1/Rp=1/20+1/20

                                              Rp=10 Ω

From Ohm's Law,

               V=IR

              3=I×10

              I=3/10

               =0.3 A

                                             

Answer 2

Explanation:

i hope this will help U .........total current will be 7.5 Ampre