Question

in the following arrangement of resistors find the total resistance in both cases.

Answer 1

In a resistors are in series so total resistance will be
2+3+6=11ohm
In b resistors are in parallel then resistance
1/r=1/2+1/3+1/6
r=1ohm

Answer 2

in series,
R1+R2+R3=Total R
2+3+6=11 ohms

In parallel,
1/R1 + 1/R2 + 1/R3=1/R
=1/2 +1/3 +1/6
=3+2+1/6
=6/6
=1 ohms

hope this helps u