In the following circuit, the output Y for all possible
inputs A and B is expressed by the truth table.
(a) A B Y
0 0 1
0 1 1
1 0 1
1 1 0
(b) A B Y
0 0 1
0 1 0
1 0 0
1 1 0
(c) A B Y
0 0 0
0 1 1
1 0 1
1 1 1
(d) A B Y
0 0 0
0 1 0
1 0 0
1 1 1
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3
Answer:
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Explanation:
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Answered by
1
The output of the first NOR gate
A+B
=Y
′
is the input for the second OR gate.
Hence, Y=
Y
′
+Y
′
=
A+B
+
A+B
=
A+B
+
A+B
=(A+B)+(A+B)=A+B
Thus the output is an OR output.
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