Question

In the following compound o bond between C2
and Cz is formed by overlapping of orbitals of C-
atoms
CH=CHCH CH,
A sp and sp
B sp and sp?
C sp? and sp
D sp2 and sp?​

Answer 1

Answer:

Here is your answer

These isomers arise because of the possibility of branching in carbon chains. For example, there are two isomers of butane, C4H10. In one of them, the carbon atoms lie in a "straight chain" whereas in the other the chain is branched. ... Pentane, C5H12, has three chain isomers.

Answer 2

Explanation:

$Answer:</p><p></p><p>Option (A): 1 J</p><p></p><p>Given Information:</p><p></p><p>Force = ( 3,2,1 ) N</p><p></p><p>Displacement = 50 cm = 0.5 m, in the direction of y-axis.</p><p></p><p>To Find:</p><p></p><p>Work Done by the body</p><p></p><p>We know that,</p><p></p><p>\boxed{Work\:\:Done = Force \times Displacement}}</p><p></p><p>Since Force is given in terms of coordinates, we first need to convert them into vector form. Converting coordinates of x to i, y to j and z to k, we get:</p><p></p><p>\implies F = 3i + 2j + z⟹F=3i+2j+z</p><p></p><p>Similarly Displacement is in y-axis. Hence we get:</p><p></p><p>\implies Displacement = 0.5 j⟹Displacement=0.5j</p><p></p><p>Taking the dot product of Force and Displacement we get:</p><p></p><p>\begin{gathered}\implies F.s = 3i.(0.5j) + 2j.(0.5j) + 1k.(0.5j)\\\\\\\implies F.s = 1.5 i.j + 1 j.j + 0.5 j.k\end{gathered}⟹F.s=3i.(0.5j)+2j.(0.5j)+1k.(0.5j)⟹F.s=1.5i.j+1j.j+0.5j.k</p><p></p><p>We know that, in dot product:</p><p></p><p>i.j = j.k = k.i = 0</p><p></p><p>i.i = j.j = k.k = 1</p><p></p><p>Hence applying it above, we get:</p><p></p><p>⇒ F.s = 1 N.m</p><p></p><p>We know 1 N.m = 1 J</p><p></p><p>Hence the Work done by the body is equal to 1 J.</p><p></p><p>Hence Option (A) is the correct answer.</p><p></p><p>$