in the following crosses write the characteristics of the progeny
a) RRYY * RRYY
b) RrYy * RrYy
c) RRYY * rryy
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Answered by
82
The characteristics of the progeny are as follows.
(a)RRYY X RRYY
Their gametes will be similar. RY and RY. Therefore all of their progenies will be RRYY (round yellow). It is dominant character.
(b) RrYy X RrYy
Their gametes will be RY, Ry, rY, ry from both parents. Therefore their progenies will be in 9:3:3:1 ratio (9 round yellow: 3 round green: 3 wrinkled yellow: 1 wrinkled green).
(c) RRYY X rryy
Their gametes will be RY and ry. Their progeny will be RrYy (all the offsprings).
(a)RRYY X RRYY
Their gametes will be similar. RY and RY. Therefore all of their progenies will be RRYY (round yellow). It is dominant character.
(b) RrYy X RrYy
Their gametes will be RY, Ry, rY, ry from both parents. Therefore their progenies will be in 9:3:3:1 ratio (9 round yellow: 3 round green: 3 wrinkled yellow: 1 wrinkled green).
(c) RRYY X rryy
Their gametes will be RY and ry. Their progeny will be RrYy (all the offsprings).
Answered by
45
A) RRYY × RRYY
➜ In the first condition given, the gametes will be same that is RY. Hence, the progeny's genotype will be RRYY and the phenotype will be Round and Yellow.
B) RrYy × RrYy
➜ In the second condition given, the gametes will be RY, Ry, rY, ry from both the parents. Hence, the progeny will be in the ratio 9 : 3 : 3 : 1. That is, 9 of them is round and yellow, 3 of them are round and green, three of them are wrinkled and yellow and one is wrinkled and green.
C) RRYY × rryy
➜ In the last condition given, the gametes will be RY and RY from the first parent and ry and ry from the second parent. And all the progeny will be RrYy.
Please refer to the image attached.
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