Question

in the following data the median runs scored by 60 top batsmen of the world in one day international cricket matches is 5000. find the missing frequencies x and y​

Answer 1

Answer:

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Answer 2

Answer:

Runs scored Number of Bats men Cumulative frequency

2500−3500 5 5

3500−4500 x 5+x

4500−5500 y 5+x+y

5500−6500 12 17+x+y

6500−7500 6 23+x+y

7500−8500 2 25+x+y

Now, N=∑f

i

=60

⇒60=25+x+y

⇒x+y=35 .....(1)

Since the median is given to be 5000, it lies in the class 4500−5500

⇒l=4500,h=1000,f=y,F=5+x and N=60

median=l+

f

2

N

−F

×h

⇒5000=4500+

y

2

60

−(5+x)

×1000

⇒500=

y

30−5−x

×1000

⇒500y=(25−x)×1000

⇒

2

y

=25−x

⇒y=50−2x

⇒2x+y=50 ........(2)

From (1) and (2) we get

2x+(35−x)=50

⇒x=15

Put x=15 in (1), we get y=20

Hence, x=15 and y=20