Question

in the following determine the set of values of p for which the given quadratic equation has real roots 2x^2+px+2=0​

Answer 1

Answer:

In ax  

2

+bx+c=0,

Discriminant D =b  

2

−4ac,

D=0, for the roots to be real and equal

In 2x  

2

+px+8=0    

Thus, we have a=2,b=p and c=8

Then D =b  

2

−4ac=0

∴p  

2

−4×2×8=0⇒p  

2

−64=0

⇒p=±8.