Math, asked by seenyachu, 9 months ago

In the following, determine whether the given quadratic equations have real roots and if so, find the roots
X2 - 2x + 1 =0

Answers

Answered by divyan678
0

Answer:

real and equal roots, roots are 2,2

Step-by-step explanation:

compare

X^2 -2X + 1=0 with

aX^2+bX+c=0

a=1,b=-2, c=1

now ,discriminant of quadratic equation=b^2-4ac

discriminate=4-4=0

If, Discriminant >0, then two roots of quadratic equation are distinct and real.

If, Discriminant =0, then two roots of quadratic equation are real and equal.

If, Discriminant < 0, then there are no real roots for given quadratic equation.

so we have two roots real and equal.

To find roots

x=(-b+√b^2-4ac)/2a and x=(-b-√b^2-4ac)/2a

the answer will be 2,2

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