In the following, determine whether the given quadratic equations have real roots and if so, find the roots
X2 - 2x + 1 =0
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Answer:
real and equal roots, roots are 2,2
Step-by-step explanation:
compare
X^2 -2X + 1=0 with
aX^2+bX+c=0
a=1,b=-2, c=1
now ,discriminant of quadratic equation=b^2-4ac
discriminate=4-4=0
If, Discriminant >0, then two roots of quadratic equation are distinct and real.
If, Discriminant =0, then two roots of quadratic equation are real and equal.
If, Discriminant < 0, then there are no real roots for given quadratic equation.
so we have two roots real and equal.
To find roots
x=(-b+√b^2-4ac)/2a and x=(-b-√b^2-4ac)/2a
the answer will be 2,2
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