Question

In the following diagram, a ray of light incident on one mirror at angle of 50 degree as shown. The angle between the mirrors is 50 degree. (a) Find the angle Ө2 (b) Calculate the sum of angles which the reflected rays make with the surfaces of mirrors 1 & 2.

Answer 1

Answer:

In the figure, the incident ray, the normal, and the angle of incidence (i) are shown. i=30.

From law of reflection i=r.  

So, construct the reflected ray at 30 degrees from the normal and let it fall on the other mirror.  

Now draw the second normal at the point of incidence and again measure the angle of incidence, and draw the angle of reflection.  

If you consider triangle AOB, one angle is ∠AOB=90  

0

 and ∠OAB is 60  

0

 

From angle sum property third angle ie ∠ABO=180  

0

−90  

0

−60  

0

=30  

0

 

So, the second incident angle will be 60  

0

.  

Hence, the second reflected angle will be 60 degrees.

Explanation:

Answer 2

Explanation:

need a diagrmam man it may be total internal reflection or critical angle