Question

in the following diagram AB=AC and DB is perpendicular to BC and EC is perpendicular to BC prove that BD=CE and AD=AE​

Answer 1

Answer:

NSWER

We have AE=AD and CE=BD.

Adding, we get AE+CE=AD+BD

⇒AC=AB.

In triangles AEB and ADC, we have

AE=AD ....... (given);

AB=AC ....... (proved);

∠EAB=∠DAC, (common angle).

By SAS postulate △AEB≅△ADC.

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