Question

In the following diagram AB is an incident ray on the plane mirror XY and CD is the reflected ray on the plane mirror YZ.If angle XBA=30 degrees,find the angle of reflection QCD on the plane mirror.

please answer the complete question step by step​

Answer 1

Answer:

30 because in this case incident ray equal to reflect ray

Explanation:

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Answer 2

Answer:

30°

Explanation:

Angle ABP = 60° (angle ABP + 30° = 90°)

Angle PBC = 60 ° (angle i = angle r)

Angle CBY = 30° (angle CBY + 60° = 90°)

In triangle BYC,

Angle BYC + Angle BCY + Angle CBY = 180° (A.S.P)

30° + 90° + Angle CBY = 180°

Angle CBY = 180° - 120°

Angle CBY = 60°

Angle BCY + Angle BCQ = 90°

60° + Angle BCQ = 90°

Angle BCQ = 30°

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